2x^2-14x-64=0

Solution for 2x^2-14x-64=0 equation:

2x^2-14x-64=0

a = 2; b = -14; c = -64;
Δ = b2-4ac
Δ = -142-4·2·(-64)
Δ = 708
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{708}=\sqrt{4*177}=\sqrt{4}*\sqrt{177}=2\sqrt{177}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{177}}{2*2}=\frac{14-2\sqrt{177}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{177}}{2*2}=\frac{14+2\sqrt{177}}{4}
$